2x^2-55x+300=0

Solution for 2x^2-55x+300=0 equation:

2x^2-55x+300=0

a = 2; b = -55; c = +300;
Δ = b2-4ac
Δ = -552-4·2·300
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-25}{2*2}=\frac{30}{4}
=7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+25}{2*2}=\frac{80}{4}
=20
$